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he heights of △ABC are drawn from vertices A and C. These heights intersect at point M. Find m∠AMC, if m∠A=70° and m∠C=80°.

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Answer: 150°

Explanation:

In the given triangle ABC ∠A=70°, ∠C=80°

therefore ∠B=180-(∠A+∠C)=180-(70+80) [sum angle property of triangle]

⇒∠B=30°

Now, heights(altitude) are drawn from vertices A and C on respective bases

they intersect at a point M. Also, we know that heights are perpendicular on the bases.

Also, point of intersection of altitudes is called orthocenter.

Now since M is orthocenter, ∠ABC+∠AMC=180° (property of orthocenter in a triangle)

⇒30°+∠AMC=180°

⇒∠AMC=180°-30°=150°

Hence in the triangle ABC, ∠AMC=150°

he heights of △ABC are drawn from vertices A and C. These heights intersect at point-example-1
User Vishnu G S
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