Question

A^-3 over a^-2b^-5 write without rational notation and move all terms to numerator

Answer 1

`\large\boxed{(a^(-3))/(a^(-2)b^(-5))=a^(-1)b^5}`

Explanation:

`(a^(-3))/(a^(-2)b^(-5))=a^(-3)\cdot(1)/(a^(-2))\cdot(1)/(b^(-5))\qquad\text{use}\ x^(-n)=(1)/(x^n)\\\\=a^(-3)\cdot a^2\cdot b^5\qquad\text{use}\ x^n\cdot x^m=x^(n+m)\\\\=a^(-3+2)b^5=a^(-1)b^5`