Answer:
Explanation:
Given that A tank holds 17 3/5 gallons after losing 36 2/3 gallons, 4 5/6 gallons,and 27 1/12 gallons in 3
Consecutive days. If at the beginning the tank was 20 3/4 gallons short of capacity.
Tank full capacity = loss for 3 days + holding of tank after losing + shortage of capacity
To add these first let us convert these into improper fractions, then take lcd to add
Full capacity =
![(88)/(5) +(110)/(3) +(29)/(6) +(325)/(12) \\=(88)/(5) +(440+58+325)/(12) \\=(1056+4115)/(60) =](https://img.qammunity.org/2020/formulas/mathematics/middle-school/maxjx8hn2d9v452crltxnp5ka5e72qpq1y.png)
gallons