Question

A^-4+b^2 when a=2 and b=3/4 answer as a reduced fraction

Answer 1

`\bf a^(-4)+b^2\implies \cfrac{1}{a^4}+b^2\qquad \begin{cases} a=2\\ b=(3)/(4) \end{cases}\implies \cfrac{1}{2^4}+\left( \cfrac{3}{4} \right)^2\implies \cfrac{1}{16}+\cfrac{3^2}{4^2} \\\\\\ \cfrac{1}{16}+\cfrac{9}{16}\implies \cfrac{1+9}{16}\implies \cfrac{10}{16}\implies \cfrac{5}{8}`