Answer:
Difference = 2.25°
Explanation:
Here we are given that at depth the Temperature T is inversely proportional to the depth x.
∝
![(1)/(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ma5752n20y6te930sh5jm5vschamdai50a.png)
![T= 4500 * (1)/(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7oamsg8sg92pn536cau1tmjqb6axdqc3uv.png)
Where 4500 is constant
Now we have to find the difference in the temperature at 1200 mts and 3750 mts
1. x=1200
![T= 4500 * (1)/(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7oamsg8sg92pn536cau1tmjqb6axdqc3uv.png)
![T= 4500 * (1)/(1200)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ajb4fswx94gk6tuxtwual7uqgjoe76kha1.png)
![T= 3.75](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2r2sjl00gq7l8k2czdjyb2ep2zcc3bdvst.png)
2. x=3750
![T= 4500 * (1)/(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7oamsg8sg92pn536cau1tmjqb6axdqc3uv.png)
![T= 4500 * (1)/(3750)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c0cgs7k8g050rbc7bc9mvsm4o2k1b0jc62.png)
![T=1.2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5wur4m4r2o4hl8h89ot52y4zmp3bq7hy4k.png)
Hence Difference is
T = 3.75 -1.20
= 2.25
Therefore The difference of the temperature at 1200 mts and 3750 mts is T=2.25°