Answer:
Point-slope form:
![y-0=(1)/(3) (x-1)\\f(x)-0=(1)/(3)(x-1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qk6uelmipkme2vosl6b4p84fltm50ge8bv.png)
Slope-intercept form:
![y=(1)/(3)x-(1)/(3) \\f(x)=(1)/(3) x-(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3eldioqutsk5xaifzlifyr5kfb4p2t628s.png)
Explanation:
You have points on that line at (-2, -1) and (1, 0). To find your slope using those points, use the slope formula.
![(y2-y1)/(x2-x1) \\\\(0-(-1))/(1-(-2)) \\\\(0+1)/(1+2) \\\\(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zwc8p2bn50yyvmgy4ro71oueqecwi21mqg.png)
Now that we have your slope, you can use your slope and one of your points to write an equation in point-slope form.
![y-y1=m(x-x1)\\y-0=(1)/(3) (x-1)\\y=(1)/(3) x-(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qbbawq4b6ik9ml6a79cgruy5n6jecogged.png)
To put it in function notation, substitute y for f(x).
![f(x)-0=(1)/(3) (x-1)\\f(x)=(1)/(3) x-(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jl4q3yc9f9nbycgjl7vxn7uy7399kl2rux.png)