What is the slope of a trend line that passes through the points (1,3) and (10,25)

Question

asked Oct 20, 2020 41.4k views

2 Answers

Mike Dotterer · Answer 1 · 2020-10-20T10:41:14+0000

Answer:

22/9

Explanation:

The slope of a line can be found by using the slope formula

$(y_2-y_1)/(x_2-x_1) \text{ where we have points } (x_1,y_1) \text{ and } (x_2,y_2) \text{ on the line }$ .

Or what I like to do is line up the points and subtract vertically, then put 2nd difference over 1st difference. Like so:

( 10 , 25)

- ( 1 , 3)

----------------

9 22

So the slope is 22/9.

You could have done it the other way too. That is:

(1 , 3)

-(10 , 25)

------------

-9 -22

So the slope is -22/-9 or just 22/9.

Moritzschaefer · Answer 2 · 2020-10-25T06:30:48+0000

Answer:

The slope of a trend line is:

m=(22)/(9)

Explanation:

The slope m of a line is calculated using the following formula:

m=(y_2-y_1)/(x_2-x_1)

For any pair of points
$(x_1, y_1),\ (x_2, y_2)$ that belong to the line

In this case the points are (1,3) and (10,25)

Therefore the slope is:

m=(25-3)/(10-1)

m=(22)/(9)