Question

g The “size” of the atom in Rutherford’s model is about 8 × 10−11 m. Determine the attractive electrostatics force between a electron and a proton separated by this distance. Answer in units of N.

Answer 1

`3.6\cdot 10^(-8) N`

Step-by-step explanation:

The electrostatic force between the proton and the electron is given by:

`F=k(q_p q_e)/(r^2)`

where

`k=9.00\cdot 10^9 Nm^2 C^(-2)` is the Coulomb constant

`q_p = 1.6\cdot 10^(-19) C` is the magnitude of the charge of the proton

`q_e = 1.6\cdot 10^(-19)C` is the magnitude of the charge of the electron

`r=8\cdot 10^(-11)m` is the distance between the proton and the electrons

Substituting the values into the formula, we find

`F=(9\cdot 10^9 ) ((1.6\cdot 10^(-19))^2)/((8\cdot 10^(-11))^2)=3.6\cdot 10^(-8) N`