Answer:
see below
Explanation:
41
-4 ≤2+4x<0
Subtract 2 from all sides
-4-2 ≤2-2+4x<0-2
-4 ≤2+4x<0
Divide all sides by 4
-6/4 ≤4x/4<-2/4
-3/2 ≤x <-1/2
graph is attached
45
2x-3 ≤-4 or 3x+1 ≥4
Lets solve the left side first
2x-3≤-4
Add 3 to each side
2x-3+3 ≤-4+3
2x ≤-1
Divide by 2
2x/2 ≤-1/2
x ≤-1/2
Now solve the right inequality
3x+1 ≥4
Subtract 1 from each side
3x+1-1 ≥4-1
3x ≥3
Divide by 3
3x/3 ≥3/3
x≥1
So we have
x ≤-1/2 or x≥1
see attached
Notice closed circles where there is a greater than equal to or less than equal to