Question

What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?

Answer 1

39698

Step-by-step explanation:

Mass= 4.6kg

latent heat= 863

ML= 4.6*863= 39698

approximately = 397 In three significant figures

Answer 2

Answer : The specific latent heat of fusion of ice is, 187.608 J/g

Explanation :

Formula used :

`Q=m* L_f`

where,

Q = heat supply = 863 KJ = 863000 J

conversion used : (1 KJ = 1000 J)

m = mass of the substance = 4.6 Kg = 4600 g

conversion used : (1 Kg = 1000 g)

`L_f` = specific latent heat of fusion = ?

Now put all the given values in the above formula, we get the specific latent heat of fusion of ice.

`863000J=4600g* L_f`

`L_f=187.608J/g`

Therefore, the specific latent heat of fusion of ice is, 187.608 J/g