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Which is the graph of f(x)=5(2)^x

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Answer:

Explanation:

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To graph f(x)=5(2)^x, first graph g(x)=(2)^x, the basic base-2 exponential function. The y-intercept is (0, 1) and the horizontal intercept is y = 0 (the x-axis). The graph begins in Quadrant II and continues in Quadrant I with no upper limit to g(x).

Once you've graphed that, "stretch" this graph vertically by a factor of 5.

The vertical intercept is now (0, 5).

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