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An engineer weighs a sample of mercury (ρ = 13.6 × 10^3 kg/m^3 ) and finds that the weight of the sample is 7.8 N. What is the sample’s volume? The acceleration of gravity is 9.81 m/s^2 . Answer in units of m^3 .

User RodeoClown
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1 Answer

3 votes

Answer:


0.0000584637\ m^(3)\\

Step-by-step explanation:

Hello

Density is a measure of mass per unit of volume


d=(m)/(v) \\\\\\

and the weight of an object is defined as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity


W=mg

let


d=13.6*10^(3) (kg)/(m^(3) )  \\ W=7.8 N\\W=mg\\m=(W)/(g) \\m=(7.8 N)/(9.81 (m)/(s^(2) ) )\\m=0.8 kg\\\\d=(m)/(v) \\v=(m)/(d) \\v=(0.8 kg)/(13.6*10^(3) (kg)/(m^(3) ))\\Volume=0.0000584637\ m^(3)

the volumen of the sample is 0.0000584637 m3

have a great day

User Halden Collier
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