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What is the solution to the system? [1]x+2y+3z=6 [2] y+2z=0 [3] z=2
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Aug 3, 2020
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What is the solution to the system?
[1]x+2y+3z=6
[2] y+2z=0
[3] z=2
Mathematics
middle-school
Daniel Williams
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Answer:
The values if x, y and z are in the image.
Aright
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Aug 9, 2020
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Aright
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