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At a distance 30 m from a jet engine, intensity of sound is 10 W/m^2. What is the intensity at a distance 180 m?

User Dogiordano
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1 Answer

7 votes

Answer:


I_(2)=0.27 W/m^2

Step-by-step explanation:

Intensity is given by the expresion:


I_(2)=Io ((r1)/(r2) )^(2)

where:

Io = inicial intensity

r1= initial distance

r= final distance


I_(2)=10 W/m^2 ((30m)/(180m) )^(2)


I_(2)=0.27 W/m^2

User Aleksander Fular
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