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A cylindrical specimen of some metal alloy having an elastic modulus of 117 GPa and an original cross-sectional diameter of 3.6 mm will experience only elastic deformation when a tensile load of 2460 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.47 mm.

User MohamedEzz
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1 Answer

2 votes

Answer:227.56 mm

Step-by-step explanation:

Given data

Elastic modulus
\left ( E\right )= 117 GPa

Diameter
\left ( d\right )=3.6mm

force applied
\left ( F\right )=2460N

Area of cross-section
\left ( A\right )=
(\pi)/(4)* d^(2)=10.18
mm^(2)

and change in length is given by


\Delta L=
(FL)/(AE)


\Delta {0.47* 10^(-3)}=
(2460* L)/(10.180* 117* 10^(3))

L=
0.47* 10^(-3)* 10.18* 117* 10^{3]

L=227.56 mm

User MiChAeLoKGB
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