Answer:
The correct option is (e) η = 0.66
Step-by-step explanation:
given data:
temperature at entry is 627 degree C
temperature at exit is 27 degree C
the efficiency of a engine is given as η
where
is temperature in kelvin at exit point
is temperature in kelvin at entry point
![\eta = (1-(27+273)/(627+273))*100](https://img.qammunity.org/2020/formulas/engineering/college/t1bngthesxbe01xskpvmim03lj2j9bpmgj.png)
η = 66.66 %