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CAN SOMEONE HELP ME FIND THE AREA OF THIS TRIANGLE

CAN SOMEONE HELP ME FIND THE AREA OF THIS TRIANGLE-example-1
User Malix
by
5.1k points

2 Answers

4 votes

Answer:


A = 73.1\ m^2

Explanation:

We calculate the height of the triangle using the function
sin(\theta)

By definition:


sin(\theta) =(h)/(hypotenuse)

Where h is the height of the triangle

In this case we have that:


\theta=35\°


hypotenuse=17

Then:


sin(35) =(h)/(17)


h=sin(35)*17\\\\\\h =9.75

Then the area of a triangle is calculated as:


A = 0.5 * b * h

Where b is the length of the base of the triangle and h is its height

In this case


b=15

So


A = 0.5 *15*9.75


A = 73.1\ m^2

User Blinxen
by
5.3k points
5 votes

Answer:

Area of triangle = 73.1 m²

Explanation:

Points to remember

Area of triangle = bh/2

Where b - base and h - height

To find the height of triangle

Let 'h' be the height of triangle

Sin 35 = h/17

h = 17 * Sin 35

= 17 * 0.5736

= 9.75 m

To find the area of triangle

Here b = 15 m and h = 9.75

Area = bh/2

= (15 * 9.75)/2

= 73.125 ≈73.1 m²

User Mike Sprague
by
5.5k points
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