Answer:
the required diameter is 0.344 m
Step-by-step explanation:
given data:
flow is laminar
flow of carbon dioxide Q = 0.005 Kg/s
for flow to be laminar, Reynold's number must be less than 2300 for pipe flow and it is given as

arrange above equation for diameter
\frac{\rho Q D}{\mu A }<2300
dynamic density of carbon dioxide = 1.47×
Pa sec
density of carbon dioxide is 1.83 kg/m³


D = 0.344 m