Question

A nozzle in a horizontal orientation is designed to have steady flowing steam exit it with a velocity of 250 m/s. If the outlet specific enthalpy of the steam is 1,986 kJ/kg, what is the required inlet specific enthalpy? Assume that heat transfer to the surroundings and the inlet steam velocity are negligible.

Answer 1

`h_(1)` = 2017.25 kJ/kg

Step-by-step explanation:

GIVEN DATA:

Exit velocity
`v_(2)` = 250 m/s

outlet enthalpy
`h_(2)`= 1986 kJ/kg

inlet velocity
`v_(1)`= 0

heat transfer Q = 0

from steady flow energy equation(SFEE) between inlet and exit point

`h_(1)+(v_(1)^(2))/(2)=h_(2)+(v_(2)^(2))/(2)+ Q`

`h_(1)=h_(2)+(v_(2)^(2))/(2)`

`h_(1)`=2017.25 kJ/kg