Question

If I add 30J of heat to a system so that the final temperature of the system is 300K, what is the change in entropy of the system? a)-1 J/K b)- 3 J/K c)- 1 J/K d)- 9 J/K e)- 10 J/K

Answer 1

0.1 J/K

Step-by-step explanation:

entropy change equation is as followed:

`\Delta S=(\Delta Q)/(T)`

where ΔS=entropy change

Q=Heat transfer

T= temperature

`\Delta S=(\Delta Q)/(T)`

`\Delta S=(30)/(300)`

`\Delta S=0.1 J/K`

hence the change in entropy of system which is
`\Delta S`is equal to 0.1 J/K