Answer:
The stress in the rod is 39.11 psi.
Step-by-step explanation:
The stress due to a pulling force is obtained dividing the pulling force by the the area of the cross section of the rod. The respective area for a cylinder is:
![A=\pi*D^2/4](https://img.qammunity.org/2020/formulas/engineering/college/xl3jegs7gyfj8x70vayl14a2uxqhxk4abm.png)
Replacing the diameter the area results:
![A= 17.76 in^2](https://img.qammunity.org/2020/formulas/engineering/college/sy14oiz1pr879zs7gjiyetuez9m029jtfu.png)
Therefore the the stress results:
![σ = 70/17.76 lb/in^2 = 39.11 lb/in^2= 39.11 psi](https://img.qammunity.org/2020/formulas/engineering/college/ni6k88c5gt5nosngw3i4q7bhw6traf5e79.png)