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Titration Practice

Use the following balanced equations for your reference:
HCI + NaOH --> NaCl + H20
2KOH + H2SO4 --> 2H20+ K2SO4
5 points
If it takes 2.0 L of 5.0 M NaOH to neutralize 5.0 of an HCl solution, what is the concentration of the HCI?
O 20M
-20 M
5.0M
20 M

User Jdw
by
7.8k points

2 Answers

2 votes

Answer:

2 M

Step-by-step explanation:

If it takes 2.0 L of 5.0 M NaOH to neutralize 5.0 of an HCl solution, the concentration of the HCI is 2 M.

2 Liters of 5 molars = 2 x 5 = 10 moles

User Demoxing
by
7.0k points
5 votes

Answer:

2 M.

Step-by-step explanation:

I mole of NaCl reacts with 1 mole of HCl ( from the equation).

2 Liters of 5 molar contains 2 * 5 = 10 moles of NaCl so this will neutralise 10 moles of HCl.

So the concentration of 5 liters of HCl must be 10/5 = 2M.

User Qballer
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6.9k points