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What is the equation of the line that passes through the point (-1, -3) and has a slope of -5?

A) y=-5x-8
B) y=-5x-16
C) y=-5x+16
D) y=-5x+8

User Keeleon
by
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1 Answer

5 votes

Answer:

A) y = -5x - 8

Explanation:

The point-slope form of an equation of a line:


y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point on a line

We have the slope m = -5, and the point (-1, -3). Substitute:


y-(-3)=-5(x-(-1))\\\\y+3=-5(x+1)

Convert to the slope-intercept form (y = mx + b):


y+3=-5(x+1) use the distributive property


y+3=-5x-5 subtract 3 from both sides


y=-5x-8

User Tom McFarlin
by
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