Answer:
Q(-2,-7)
See attachment
Explanation:
We need to form a simultaneous equation and solve.
The point P has coordinates (1,8). Let the other point Q also have coordinate (x,y).
Then the average rate of change is the slope of the secant line connecting P(1,8) and Q(x,y) and this has a value of 5.
![\implies (8-y)/(1-x)=5](https://img.qammunity.org/2020/formulas/mathematics/high-school/w8qo1jr7z0srwnait31c278sgkb9d5em73.png)
![\implies 8-y=5(1-x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mg5lhtagoinj1uf6bhj0mauitdy0vfeyxe.png)
![\implies y=5x-3...(1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/bx4ukdtifmt7xglpq77qv74nyf1gmax95p.png)
This point Q also lies on the given parabola whose equation is
![y=-(x-2)^2+9...(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/yppzrate66ia89msrxc5mubkjiprl7pu11.png)
Put equation (1) into (2) to get:
![5x+3=-(x-2)^2+9](https://img.qammunity.org/2020/formulas/mathematics/high-school/yteeisf8739tyqqvfh3tz346c3k1raiqw7.png)
![5x+3=-(x^2-4x+4)+9](https://img.qammunity.org/2020/formulas/mathematics/high-school/rgc42isefqxnuym3bd3n9oz5a1is94gv52.png)
![5x+3=-x^2+4x-4+9](https://img.qammunity.org/2020/formulas/mathematics/high-school/5103z1btdydqpbieqfi811s1w2ejshwqvl.png)
![5x+3=-x^2+4x+5](https://img.qammunity.org/2020/formulas/mathematics/high-school/dk0q3bo213vbxq7yflkvw0akosi4q9jbmi.png)
![x^2+x-2=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/telgytphpd2bkn29eama8ggfntklain4qh.png)
![(x-1)(x+2)=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/eedgl4j5lyrby72yjgt8j4ya84545j5ev8.png)
![x=1,x=-2](https://img.qammunity.org/2020/formulas/mathematics/high-school/gz8uzbhoq5awfa7kqvqwed7tg1lec3ytsm.png)
When x=-2, y=5(-2)-3=-7
Therefore the required point is Q(-2,-7)