Question

Which of the following are solutions to the equation below? Check all that apply (2x+3)^2=10

Answer 1

Answer: E .√10 - 3 / 2 or

c. -√10 - 3 / 2

Explanation:

(2x + 3)^2 = 10

take the square root of bothside

√(2x + 3)^2 = ±√10

2x + 3 = ±√10

subtract 3 from bothside

2x = ±√10 - 3

Divide bothside by 2

x = ±√10 - 3 / 2

Either x = √10 - 3 / 2 or

x = -√10 - 3 / 2

Answer 2

Option C and E are correct.

Explanation:

We need to solve the following equation

(2x+3)^2=10

taking square root on both sides

`√((2x+3)^2)=√(10)\\2x+3=\pm√(10)`

Now solving:

`2x+3=√(10) \,\,and\,\,2x+3=-√(10)\\2x=√(10)-3 \,\,and\,\,2x=-√(10)-3\\x=( √(10)-3)/(2) \,\,and\,\,x=(-√(10)-3)/(2)`

So, Option C and E are correct.