2 Answers

Oasis Feng · Answer 1 · 2020-04-27T10:35:43+0000

First you must solve system of equations.

Multiply the first equation by 4 and second one by 3.

You result with,

$16x-12y=4 \\15x+12y=27$

Add the equations so y terms cancel out.

$31x=31\Longrightarrow x=1$

Insert x that was found in either one of the equations. I'll pick first one.

$4\cdot1-3y=1$

Solve for y.

$-3y=-3 \\y=1$

The solutions to the system of equations are,

$\boxed{x=1},\boxed{y=1}$

Therefore the number missing is 1.

Hope this helps.

r3t40

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