Question

What is -3x^2-4x-4=0

Answer 1

no real solution

Explanation:

`-3x^2-4x-4=0\qquad\text{change the signs}\\\\3x^2+4x+4=0\\\\\text{use the quadratic formula:}\\\\\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac<0,\ \text{then an equation has no solution}\\\\\text{if}\ b^2-4ac=0,\ \text{then an equation has one solution}\ x=(-b)/(2a)\\\\\text{if}\ b^2-4ac>0,\ \text{then an equation has two solutions:}\ x=(-b\pm√(b^2-4ac))/(2a)`

`\text{We have}\ a=3,\ b=4,\ c=4.\\\\\text{Substitute:}\\\\b^2-4ac=4^2-4(3)(4)=16-48=-32<0\\\\\bold{no\ real\ solution}`