Answer:
0.479 dm^3 (or 479 cm^3)
Step-by-step explanation:
First, calculate the no. of moles in 110g of Pb(NO3)2.
According to the periodic table, molar mass of Pb is 207.2, N is 14,0, O is 16.0
so, the molar mass of Pb(NO3)2 = 207.2 + (14.0 + 16.0 x 3) x 2 = 331.2
With the formula:
no. of moles = mass/molar mass
no. of moles in 110g of Pb(NO3)2 = 110 / 331.2
= 0.33213 mol
Then, with the formula:
molarity = no. of moles / volume
0.694 = 0.33213 / v
v = 0.479 dm^3 (or 479 cm^3)
Therefore, the volume needed is 0.479 dm^3 (or 479 cm^3)