Question

NEED HELP WITH MATH QUESTION ITS ABOUT FINDING AREA OF A TRIANGLE !! I WOULD BE REALLY GRATEFUL IS SOMEONE HELPED ME WITH A FEW QUESTIONS AFTER THIS

Answer 1

65.8 in²

Explanation:

Given a triangle with 2 sides and the included angle then the area (A) is

A = 0.5 × a × b × sinΘ

where a, b are the 2 sides and Θ the included angle

here a = 18, b = 12 and Θ = 147°, hence

A = 0. 5 × 18 × 12 × sin147°

= 108 × sin147° ≈ 65.8 ( to the nearest tenth )

Answer 2

The area of triangle is 59.2 in².

Explanation:

If a, b and c are three sides of a triangle then the area of triangle by heron's formula is

`A=\sqrt{s(s-a)(s-b)(s-c)` .... (1)

where,

`s=(a+b+c)/(2)`

From the given figure it is clear that the length of sides are 12 in, 18 in and 28.8 in. The value of s is

`s=(12+18+28.8)/(2)=29.4`

Substitute s=29.4, a=12, b=18 and c=28.8 in equation (1).

`A=√(29.4(29.4-12)(29.4-18)(29.4-28.8))`

`A=√(3499.0704)`

`A=59.15294`

`A\approx 59.2`

Therefore the area of triangle is 59.2 in².