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(x^2y^3) = (xy^a)^b

In the equation above, a and b are constants, and the
equation is true for all x > 0 and y > 0. What is the
value of a ?

The correct answer is C, 3/2

Thanks!

(x^2y^3) = (xy^a)^b In the equation above, a and b are constants, and the equation-example-1

1 Answer

6 votes

Answer:

C.
(3)/(2)

Explanation:

To find the value f b, we need to compare the exponents.

The given exponential equation is:


( {x}^(2) {y}^(3) )^(3) = ( {x} {y}^(a) )^(b)

Recall and apply the following rule of exponents.


( {x}^(m) )^(n) = {x}^(mn)

We apply this rule on both sides to get:


{x}^(2 * 3) {y}^(3 * 3) = {x}^(b) {y}^(ab)

Simplify the exponents on the left.


{x}^(6) {y}^(9) = {x}^(b) {y}^(ab)

Comparing exponents of the same variables on both sides,


b = 6 \: and \:\: ab = 9


\implies \: 6b = 9

Divide both sides by 6.


b = (9)/(6)


b = (3)/(2)

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