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what is change in internal energy if 30j of heat are released from a system that does 50j of work on its surroundings

User Jenna Leaf
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2 Answers

6 votes

Answer: -80 J

Step-by-step explanation:

User Elbowich
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0 votes

Answer:

-80 J

Step-by-step explanation:

The first law of thermodynamics states that:


\Delta U = Q - W

where


\Delta U is the change in internal energy of the system

Q is the heat absorbed by the system

W is the work done by the system

In this problem, we have:

Q = -30 J is the heat released by the system (negative because the system releases it)

W = +50 J is the work done by the system on the surrounding (positive since it is done by the system)

Therefore, the change in internal energy is


\Delta U = -30 J - (+50 J) = -80 J

User Austio
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