Answer:
a.
![P = (1)/(1000)](https://img.qammunity.org/2020/formulas/mathematics/college/r4sc1r6x282oh2liqimuo23bd4gydegapk.png)
b.
![P = (3)/(500)](https://img.qammunity.org/2020/formulas/mathematics/college/eyghahe93rmkcekqv9uoejkoxv0k20j49d.png)
Explanation:
To win the 'straight play' a ticket must have the exact number. Given that there are 1000 numbers between 000 and 999. The probability of winning in striaght play is:
![P = (1)/(1000)](https://img.qammunity.org/2020/formulas/mathematics/college/r4sc1r6x282oh2liqimuo23bd4gydegapk.png)
To win in a box play, a ticket can have the three digit in daily order.
Given three numbers A, B and C. There are 6 ways to arrange the numbers:
ABC, ACB, BAC, BCA, CAB, CBA.
Therefore the probability is:
![P = (3)/(500)](https://img.qammunity.org/2020/formulas/mathematics/college/eyghahe93rmkcekqv9uoejkoxv0k20j49d.png)