Question

Write the slope-intercept form of the equation that passes through the point (4,-6) and is parallel to the line y = -3/4x - 5 y = -3/4x - 3 y = -3/4x + 3 y = 4/3x + 2/3 y = 4/3x - 34/3

Answer 1

`\large\boxed{y=-(3)/(4)x-3}`

Explanation:

The slope-intercept form of an equation of a line:

y = mx + b

m - slope

b - y-intercept

Parallel lines have the same slope.

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We have the equation of the line:
`y=-(3)/(4)x-5`

The slope is
`m=-(3)/(4)`.

Put the value of the slope and the coordinates of the point (4, -6) to an equation of a line:

`-6=-(3)/(4)(4)+b`

`-6=-3+b` add 3 to both sides

`-3=b\to b=-3`

Finally:

`y=-(3)/(4)x-3`