Answer:
Option 2nd , 3rd and 5th are correct.
Explanation:
Given:
Given line passes through points ( -2 , -4 ) and ( 4 , 2 )
Coordinate of the Point P( 0 , 4 )
To find: Point which lie on the line parallel to given line and passes through point P.
Slope of the given line =
![(y_2-y_1)/(x_2-x_1)\:=\:(-4-2)/(-2-4)\:=\:(-6)/(-6)\:=\:1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2xch44c7eig0chsqegqrwl9thxconid1pe.png)
We know that slope of parallel lines ara equal.
So, Using Slope-Point form we get equation of line,
![y-y_1=m(x-x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lwv5ftdd36i4idvu50qxfdgwxhdby4wlt5.png)
y - 4 = 1 ( x - 0 )
y - 4 = x
x - y = -4
Option 1:
x = -4 , y = 2
LHS = -4 - 2 = -6 ≠ RHS
Thus, This is not required point.
Option 2:
x = -1 , y = 3
LHS = -1 - 3 = -4 = RHS
Thus, This is required point.
Option 3:
x = -2 , y = 2
LHS = -2 - 2 = -4 = RHS
Thus, This is required point.
Option 4:
x = 4 , y = 2
LHS = 4 - 2 = 2 ≠ RHS
Thus, This is not required point.
Option 5:
x = -5 , y = -1
LHS = -5 - (-1) = -4 = RHS
Thus, This is required point.
Therefore, Option 2nd , 3rd and 5th are correct.