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Write ln2x+2lnx-ln3y as a single logarithm.

a. ln(2x/3y)

b. ln(3x/3y)

c. ln(2x^3/3y)

d. ln(x^3/3y)

Answer is C. ln(2x^3/3y) on Edge!

User Minions
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Answer:

Option C.
ln((2x^(3))/(3y))

Explanation:

The given logarithmic expression is:


ln(2x)+2ln(x)-ln(3y)

Using the power rule of logarithms:
blog(a)=log(b)^(a), the above expression can be written as:


ln(2x)+ln(x)^(2)-ln(3y)

Using the product rule of logarithms:
log(a)+log(b) =log(ab), the above expression can be simplified further to:


ln(2x * x^(2)) - ln(3y)\\\\=ln(2x^(3))- ln(3y)

Using the quotient rule of logarithms:
log(a)-log(b)=log((a)/(b)), the above expression can be written as:


ln((2x^(3))/(3y))

Hence option C gives the correct simplified answer.

User SebastianRiemer
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