Answer:
(3x-2) (9x^2 + 6x +4)
Explanation:
27x^3−8
This is the difference of cubes
a^3 - b^3 = (a-b)(a^2 + ab + b^2)
a^3 =27x^3 so a = 3x
b^3 =8 so b=2
a^2 = (3x)^2 = 9x^2 ab = (3x)*2 = 6x b^2 = 2^2 =4
27x^3 -8 = (3x-2) (9x^2 + 6x +4)
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