Question

A force of 32.5N stretches a spring of 0.500cm. What force will stretch a similar spring 1.60 cm?​

Answer 1

104 N

Step-by-step explanation:

Calculate the spring stiffness:

F = kx

32.5 N = k (0.500 cm)

k = 65 N/cm

Find the force for the new length:

F = kx

F = (65 N/cm) (1.60 cm)

F = 104 N