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A solid weighs 277.5 g in air and 212.5 g when totally immersed in the liquid of density 0.9 g/ cc. Calculate the density of the solid.​

User Bo Chen
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1 Answer

5 votes

Answer:

3.842 g/cm³

Step-by-step explanation:

Three forces are acting on the solid: weight, normal force (apparent weight), and buoyancy.

∑F = ma

N − m g + ρf V g = 0

N − ρs V g + ρf V g = 0

ρs is the density of the solid and ρf is the density of the fluid it is submerged in.

Writing normal force in terms of apparent mass, N = mₐ g:

mₐ g − ρs V g + ρf V g = 0

mₐ − ρs V + ρf V = 0

mₐ = ρs V − ρf V

mₐ = V (ρs − ρf)

V = mₐ / (ρs − ρf)

Volume is constant, so:

mₐ / (ρs − ρf) = mₐ / (ρs − ρf)

277.5 / (ρ − 0.0) = 212.5 / (ρ − 0.9)

Cross multiply and solve:

212.5ρ = 277.5 (ρ − 0.9)

212.5ρ = 277.5ρ − 249.75

249.75 = 65ρ

ρ = 3.842

The density of the solid is 3.842 g/cm³.

User Belliez
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