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Complete the three-by-three magic square (that is,the sums of the numbers in each row, in each column and in each of the diagonals are the same) using

User Rlarroque
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\displaystyle\\\text{We will use numbers from 1 to 9.}\\\\1+2+3+4+5+6+7+8+9=(9(9+1))/(2)=(9*10)/(2)=(90)/(2)=\boxed{\bf45}\\\\\text{the sums of the numbers in each row, in each column are }=(45)/(3)=\boxed{\bf15}\\\\\text{Solution:}\\\\\boxed{\,2\,}\boxed{\,7\,}\boxed{\,6\,}\\\boxed{\,9\,}\boxed{\,5\,}\boxed{\,1\,}\\ \boxed{\,4\,}\boxed{\,3\,}\boxed{\,8\,}\\\\\text{Convenient rotation of the square gives 8 solutions.}

User Akp
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