60.7k views
3 votes
(3x^2-5x-7x^4)-(-2x^3+6x^4-5x^2)

User Tomfmason
by
8.3k points

2 Answers

3 votes

Answer:

-x(13x³ - 2x² - 8x + 5)

Explanation:

1. Distribute the negative to the numbers inside the parenthesis. Remember that two negatives multiplied will make a positive, and a negative and a positive will become a negative.

3x² - 5x - 7x^4 + 2x³ - 6x^4 + 5x²

2. Combine like terms. Remember that only numbers with the same number and exponents can be combined.

3x² - 5x - 7x^4 + 2x³ - 6x^4 + 5x²

8x² - 5x - 7x^4 + 2x³ - 6x^4

8x² - 5x - 13x^4 + 2x³

3. Rewrite the answer in descending order of powers.

-13x^4 + 2x³ + 8x² - 5x

4. Simplify The equation. The terms all have x in common, so we will take that out first. The smallest amount of x's any term has is one (-5x only has one x), so the most we can take out is one x. We will do this by lowering the power of every x by one.

x(-13x³ + 2x² + 8x - 5)

5. Since 13 and 5 are prime and do not go into 2 or 8 we will not be simplifying the coefficients. However, the last thing we can do is take out a negative.

-x(13x³ - 2x² - 8x + 5)

User CGS
by
7.7k points
5 votes

Answer:

-13x^4+2x^3+8x^2-5x

Explanation:

(3x^2-5x-7x^4)-(-2x^3+6x^4-5x^2)

= 3x^2-5x-7x^4+2x^3-6x^4+5x^2

= -13x^4+2x^3+8x^2-5x

User Crazyrems
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories