Question

AgNO3(aq)+Na3PO4(aq) ionic equation

Answer 1

3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻

Step-by-step explanation:

An ionic equation is a chemical equation where the electrolytes in aqueous solution are expressed as dissociated ions.

For the reaction:

3AgNO₃(aq) + Na₃PO₄(aq) → Ag₃PO₄(s) + 3 NaNO₃(aq)

AgNO₃(aq), Na₃PO₄(aq) and NaNO₃(aq) are dissociated in water thus:

AgNO₃(aq) → Ag⁺ + NO₃⁻

Na₃PO₄(aq) → 3Na⁺ + PO₄³⁻

NaNO₃(aq) → Na⁺ + NO₃⁻

The ionic equation is:

3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻

I hope it helps!

Answer 2

All species are "(aq)" unless marked otherwise:

molecular: Na3PO4 + 3 AgNO3 → Ag3PO4(s) + 3 NaNO3
total ionic: 3 Na{+} + PO4{3-} + 3 Ag{+} + 3 NO3{-} → Ag3PO4(s) + 3 Na{+} + 3 NO3{-}
net ionic: PO4{3-} + 3 Ag{+} → Ag3PO4(s)

K2SO4(aq)+Na2CO3(aq) no reaction

molecular: Pb(NO3)2 + Na2CO3 → PbCO3(s) + 2 NaNO3
total ionic: Pb{2+} + 2 NO3{-} + 2 Na{+} + CO3{2-} → PbCO3(s) + 2 Na{+} + 2 NO3{-}
net ionic: Pb{2+} + CO3{2-} → PbCO3(s)

molecular: BaCl2 + 2 KOH → Ba(OH)2(s) + 2 KCl
total ionic: Ba{2+} + 2 Cl{-} + 2 K{+} + 2 OH{-} → Ba(OH)2(s) + 2 K{+} + 2 Cl{-}
net ionic: Ba{2+} + 2 OH{-} → Ba(OH)2(s)