Answer:
-512
Explanation:
Evaluate y^5/(x^3/2^2) where x = 2 and y = -4:
(y^5)/(2^(-2) x^3) = (-4)^5/2^(-2)×1/2^3
2^3 = 2×2^2:
(-4)^5/2^(-2) 1/(2×2^2)
2^2 = 4:
(-4)^5/((2×4)/2^2)
2×4 = 8:
(-4)^5/(8/2^2)
2^(-2) = 1/4:
((-4)^5/8)/(1/4)
(-4)^5 = (-1)^5×4^5 = -4^5:
((-4^5)/8)/(1/4)
4^5 = 4×4^4 = 4 (4^2)^2:
((-4 (4^2)^2)/8)/(1/4)
4^2 = 16:
((-4×16^2)/8)/(1/4)
| 1 | 6
× | 1 | 6
| 9 | 6
1 | 6 | 0
2 | 5 | 6:
((-4×256)/8)/(1/4)
4×256 = 1024:
((-1024)/8)/(1/4)
Multiply the numerator by the reciprocal of the denominator, ((-1024)/8)/(1/4) = (-1024)/8×4:
(-1024×4)/8
(-1024)/8 = (8 (-128))/8 = -128:
-128×4
-128×4 = -512:
Answer: -512