Question

According to the​ label, a can of soup holds an average of 307 ​grams, with a standard deviation of 4.1 grams. Assuming a normal​ distribution, what is the probability that a can will be sold that holds more than 308 ​grams?

Answer 1

Answer: 0.4052

Explanation:

Given : Mean :
`\mu=\text{307 ​grams}`

Standard deviation :
`\sigma = \text{4.1 grams}`

The formula for z -score :

`z=(x-\mu)/(\sigma)`

For x=308 ,

`z=(308-307)/(4.1)=0.24390\approx0.24`

The p-value =
`P(z>0.24)=1-P(z<0.24)`

`=1-0.5948348= 0.4051652\approx0.4052`

Hence, the probability that a can will be sold that holds more than 308 ​grams =0.4052.