Question

Batman (mass = 88.8 kg) jumps straight down from a bridge into a boat (mass = 530 kg) in which a criminal is fleeing. The velocity of the boat is initially +14.5 m/s. What is the velocity of the boat after Batman lands in it?

Answer 1

The velocity of the boat after Batman lands in it is 2.08 m/s.

Step-by-step explanation:

Given that,

Mass of batman
`m_(1)= 88.8\ kg`

Mass of boat
`m_(2)=530\ kg`

Initial velocity = 14.5 m/s

We need to calculate the velocity of boat

Using conservation of momentum

`m_(1)u=(m_(1)+m_(2))v`...(I)

Where,
`m_(1)`=mass of batman

`m_(2)` =mass of boat

u=initial velocity

v = velocity of boat

Put the value in the equation

`88.8*14.5=530+88.8* v`

`v=(88.8*14.5)/(530+88.8)`

`v=2.08\ m/s`

Hence, The velocity of the boat after Batman lands in it is 2.08 m/s.