Question

What is the percent composition of NaHCO3?

23.20% Na, 4.26% H, 18.41% C, and 54.13% O
24.21% Na, 4.35% H, 12.26% C, and 59.18% O
27.36% Na, 1.20% H, 14.30% C, and 57.14% O
30.44% Na, 2.12% H, 10.25% C, and 60.19% O

Answer 1

Great Explanation and Answer Above, Just confirming its the correct answer.

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C: 27.36% Na, 1.20% H, 14.30% C, and 57.14% O

Step-by-step explanation:

Answer 2

Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Step-by-step explanation:

Percent Composition is defined as the %age by mass of each element present in a compound. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

a) Na = 22.99 g/mol

b) H = 1.01 g/mol

c) C = 12.01 g/mol

d) O₃ = 16.0 × 3 = 48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

Na = 22.99 g/mol

H = 1.01 g/mol

C = 12.01 g/mol

O₃ = 48 g/mol

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Total 84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

= 22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 27.36 %

For H:

= 1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 1.20 %

For C:

= 12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 14.29 % ≈ 14.30 %

For O:

= 48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

= 57.13 % ≈ 57.14 %