Question

A current density of 7.00 10-13 A/m2 exists in the atmosphere at a location where the electric field is 185 V/m. Calculate the electrical conductivity of the Earth's atmosphere in this region.

Answer 1

electrical conductivity is given as

`\sigma = 3.8 * 10^(-15)`

Step-by-step explanation:

For a current carrying conductor we will have relation between current density and electric field inside the conductor as

`j = \sigma E`

here we have

current density = j

electric field = E

given that

`j = 7.00 * 10^(-13)`

`E = 185 V/m`

now we will have

`\sigma = (j)/(E)`

`\sigma = (7.00 * 10^(-13))/(185)`

`\sigma = 3.8 * 10^(-15)`