Question

During a volleyball serve, the ball leaves the hand with an initial velocity of 10 m/s angled 41 degrees from the horizontal. What are the horizontal and vertical velocities of the ball?

Answer 1

7.55 m/s, 6.56 m/s

Step-by-step explanation:

v = 10 m/s, theta = 41 degree

Horizontal component of velocity = v x Cos theta = 10 x Cos 41 = 7.55 m/s

Vertical component of velocity = v x Sin theta = 10 x Sin 41 = 6.56 m/s