HELPPP MEEEEEEE!!!!!!!! plz Which ordered pairs are solutions to the inequality 2x+3y≥−1 ? Select each correct answer. (2, −1) (−6, 0) (−2, 1) (0, 1) (0, −1)

Question

asked Feb 16, 2020 140k views

1 Answer

Solx · Answer 1 · 2020-02-20T19:37:37+0000

Answer:

(2,-1)

(-2,1)

(0,1)

Explanation:

Let's plug in the points given and see which satisfy it (make it true).

2x+3y>=-1

Test (2,-1)

2(2)+3(-1)>=-1

4 + (-3)>=-1

1>=-1 This is true 1 is greater than -1 so (2,-1) works!

Test (-6,0)

2(-6)+3(0)>=-1

-12 + 0 >=-1

-12 >=-1 This is not true. -12 is not greater than -1.

Test (-2,1)

2(-2)+3(1)>=-1

-4 + 3 >=-1

-1 >=-1 This is true. -1 does equal -1.

Test (0,1)

2(0)+3(1)>=-1

0 + 3 >=-1

3>=-1 This is true. 3 is greater than -1.

Test (0,-1)

2(0)+3(-1)>=-1

0 + (-3)>=-1

-3>=-1 This is false. -3 is not greater than -1.