Answer:
a)
3.25 x 10⁵ m/s
b)
8.7 x 10²⁰ N
Step-by-step explanation:
(a)
w = angular speed of the star = 1.8 x 10⁻¹⁵ rad/s
r = radius of the orbit = 1.9 x 10⁴ ly = 1.9 x 10⁴ (9.5 x 10¹⁵) m = 18.05 x 10¹⁹ m
tangential speed of the star is given as
v = r w
v = (18.05 x 10¹⁹) (1.8 x 10⁻¹⁵)
v = 32.5 x 10⁴ m/s
v = 3.25 x 10⁵ m/s
b)
m = mass of the star = 1.48 x 10³⁰ kg
Net force on the star to keep it moving is given as
F = m r w²
F = (1.48 x 10³⁰) (18.05 x 10¹⁹) (1.8 x 10⁻¹⁵)²
F = 8.7 x 10²⁰ N