Question

40:14

The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x em and 3x cm.
Rounded to the nearest tenth, what is the greatest possible value of x?
LE
6,3
6.4
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Answer 1

x LE 6.3.

Explanation:

For an obtuse triangle

c^2 > a^2 + b^2 where c is the longest side. So:

20^2 > x^2 + (3x)^2

400 > 10x^2

x^2 < 40

x < 6.324

x < 6.3.